Calculate the empirical formulae of the following compound.Please give solution
1. Calculate the empirical formulae of the following compound.Please give solution
Stoichiometry
Ar Fe = 56
Ar O = 16
Mass of Fe = 11.2 grams
Mass of O = 16.0 - 11.2 = 4.8 grams
Ratio beween mass and Ar
Fe : O = [11.2/56] : [4.8/16]
Fe : O = 0.2 : 0.3
Fe : O = 2 : 3
Empirical formulae is Fe₂O₃
2. If the mass is found as following = Copper : 0,52g H2O : 0,245g Chloride : 23.872g Calculate the empirical formula of substance in the reaction.
gangerti kak aku juga bingung
3. An experimental catalyst used in the polymerization of butadiene is 23,3% Co.25,3% Mo, and 51,4% Cl, what is the empirical fomula of the catalyst?
cari koefisien dari peraamaan persentase Co = 1
Mo = 1
Cl = 2
rumus empiris = CoMoCl2
4. Homestay program in Malaysia is aimed to promote various Malay culture and local lifestyle to the guests especially tourists. The usual practice of staying together with host families where tourists have the opportunity to interact and experience the life style and culture of the host family as well as the local community is essential aspects to be looked into in ensuring the programs are in line with syariah. The elements and criteria of a homestay which includes food and beverages ethics, programs, safety, services, neighborhood rights facilities, and accommodation should be complied to suit the needs and requirements of SCH in Malaysial In the future, an empirical work should be conducted in order to get better findings for this study as this paper is regarded as an exploratory study. It is hope that through this, proposed legal framework of Shariah Compliant Homestay will improve the services of homestays and cater the needs and necessities of travellers and tourists and thus will further enhance the tourism industry in Malaysia.how to make a conclusions with the above statement ?
Make it into points;
•The Homestay program is aimed to promote various Malay culture and local lifestyle
•Tourists have the opportunity to interact and experience the lifestyle and culture from the host family.
•The criteria of the Homestay is food and beverages ethics, programs, safety and service, neighborhood right facilities, and accomodation.
•The Answer is in the attachment.
5. A compound contains 4.04% hydrogen, 24.24% carbon, and 71.72% chlorine. Relative atomic masses: H = 1, C = 12, Cl = 35.5 Relative molecular mass of the compound = 99 Given this information, find the empirical formula and the molecular formula of the compound.
Menentukan Rumus Empiris berarti kita menentukan perbandingan paling kecil dari tiap jumlah molekulpertama kita tentukan rumus molekul dengan membagi jumlah kadar atom dengan massa relatifnya
H = 4.04 ÷ 1 = 4,04 dibulatkan ke bawah → 4
C = 24.24 ÷ 12 = 2.02 dibulatkan ke bawah → 2
Cl = 71.72 ÷ 35.5 = 2.02... dibulatkan ke bawah → 2
Didapatkan rumus molekularnya adalah C2H2Cl2Kemudian perkecil perbandingannya maka didapatkan CH2Cl6. Combustion analysis of 1.200 g of an unknown compound containing carbon, hydrogen, and oxygen produced 2.086 g of CO2 and 1.134 g of H2O. What is the empirical formula of the compound?
Rumus Empirisnya adalah CH2O.
7. Which formula represents the empirical formula of a compound? A.H202 B.C6H12 c. C2H4 D.CH4O
Jawaban:
b.c6h12
Penjelasan:
maaf kalo salah
8. Apa itu empirical observable
Jawaban:
derived from or relating to experiment and observation rather than theory 2 (of medical treatment) based on practical experience rather than scientific proof 3 (Philosophy) a (of knowledge) derived from experience rather than by logic from first principles Compare → a priori → a posteriori b (of a proposition) subject, at least theoretically, to verification Compare → analytic → 4 → synthetic → 4 4 of or relating to medical quackery n 5 (Statistics) the posterior probability of an event derived on the basis of its observed frequency in a sample maap kalo salah9. An empirical study of data warehouse implementation effectiveness ?
The decisional analysis is a complex, iterative, and exploratory process based on a sequence of queries issued against the data warehouse. The efficiency of the decisional activity depends on the quality of the stored data in the data warehouse, while its effectiveness is related to the analysis tools. In this paper, we discuss both these aspects in the context of a service company, with the aim of analyzing the trend of railway booking data. In particular, the back-end and front-end software solutions of data ware-housing implementation are presented, which permit to met the customer needs while preserving the desired requirements of efficiency and effectiveness.
10. The explosive known as RDX contains 16.22% carbon, 2.72% hydrogen, 37.84% nitrogen, and 43.22% oxygen by mass. Determine the empirical formula of the compound.
[C] : 16,22% (w/w)
[H] : 2,72% (w/w)
[N] : 37,84% (w/w)
[O] : 43,22% (w/w)
the emperical formula of the compound : .. ?
Answered
Step 1
Deterime mass of each elements in RDX
% (w/w) means X grams solute in 100 grams solvent.
[C] : 16,22% means 16,22 g of C in 100 g
[H] : 2,72% means 2,72 g of H in 100 g
[N] : 37,84% means 37,84 g of N in 100 g
[O] : 43,22% means 43,22 g of O in 100 g
Step 2
Determine moles of each elements
moles : mass / Ar
moles of C : 16,22 g / 12 g/moles
C : 1,352 moles
moles of H : 2,72 g / 1 g/moles
H : 2,72 moles
moles of N : 37,84 g / 14 g/moles
N : 2,703 moles
moles of O : 43,22 g / 16 g/moles
O : 2,701 moles
Step 3
Compare moles of each elements so we are going to find out the empirical formula of the compound.
m : moles
m. of C : m. of H : m. of N : m. O
1,352 : 2,720 : 2,703 : 2,701
——————————————— (1,352)
1 : 2,01 : 2,00 : 2,00
CH2N2O2
(CH2N2O2)n
So, the empirical formula of the compound is (CH2N2O2)n
Wish it helped
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11. An unknown plastic foam consists of C, H, and N. The combustion of these compounds yields, N2, H2O, CO2 and as products. If the combustion of 9.72 g of the unknown substance yields 1.45 g N2 and 6.64 g H2O , what is its empirical formula?
Since we're going to need to calculate molar masses, let's start with looking up the atomic weights of the associated elements. Atomic weight carbon = 12.0107 Atomic weight nitrogen = 14.0067 Atomic weight hydrogen = 1.00794 Atomic weight oxygen = 15.999 Molar mass H2O = 2 * 1.00794 + 15.999 = 18.01488 g/mol Molar mass N2 = 2 * 14.0067 = 28.0134 g/mol Now calculate the number of moles of H2O and N2 we have Moles H2O = 6.63 g / 18.01488 g/mol = 0.368029096 moles Moles N2 = 1.46 g / 28.0134 g/mol = 0.052117915 moles Since there's 2 hydrogen atoms per H2O molecule, we have 2 * 0.368029096 mol = 0.736058192 moles of hydrogen. The mass of that hydrogen is 0.736058192 mol * 1.00794 g/mol = 0.741902494 g Since there's 2 nitrogen atoms per N2 molecule, we have 2 * 0.052117915 mol = 0.10423583 moles We already know the mass of nitrogen we have. Now we need to determine the mass of carbon we have and the number of moles of carbon. Subtract the know mass of hydrogen and nitrogen from the total mass of Aniline. So 9.71 g - 0.741902494 g - 1.46 g = 7.508097506 g Moles carbon = 7.508097506 g / 12.0107 g/mol = 0.625117396 mol We now have the ratio of carbon : hydrogen : nitrogen of 0.625117396 : 0.736058192 : 0.10423583 We need to get a ratio of small integers that closely approximates the above ratio. Start by dividing all the numbers by the smallest of the numbers. Giving: 5.997145089 : 7.061470053 : 1 All three of those values are acceptably close to integers with the ratio of 6:7:1 So the empirical formula of Aniline is C6H7N
semoga mwmbantu
12. A 3.245 gram sample of a titanium chloride was reduce with sodium metallic titanium. After the resultant sodium chloride was washed out. The residual titanium metal was dried. And weighted 0.819 gram. What is the empirical formula of titanium chloride?
[tex]Titanium \ c. + Sodium \ m. \ titanium \rightarrow Sodium \ c. + Titanium \\ mass_{titanium} = 0.819 \ gram \\ mass_{titanium \ c.} = 3.245 \ gram \\ mass_{chloride} = mass_{titanium \ c.} - mass_{titanium} \\ mass_{chloride} = 3.245 - 0.819 = 2.426 \ gram \\ \\ mole_{titanium} : mole_{chloride} = \frac{mass_{titanium}}{molar \ mass_{titanium}} : \frac{mass_{chloride}}{molar \ mass_{chloride}} \\ molar \ mass_{titanium} = 47.867 \ g/mol \\ molar \ mass_{chloride} = 35.453 \ g/mol[/tex][tex]mole_{titanium} : mole_{chloride} = \frac{0.819}{47.867} : \frac{2.426}{35.453} \\ mole_{titanium} : mole_{chloride} = 0.017 : 0.068 \\ mole_{titanium} : mole_{chloride} = 1 : 4 \\ \\ In \ conclusion, \ the \ empirical \ formula \ for \ titanium \ chloride \ is: \\ TiCl_4[/tex]
13. Beryllium forms a compound with chlorine that hasthe empirical formula becl2. how would you determinewhether it is an ionic compound?
Answer :
it's ionic compound
Explain:
because group 1A to 3A is metal element (except hydrogen and boron)
apart from group 1A to 3A, is non-metal element (4A, 5A, 6A, 7A, 8A)
beryllium is in 2A group so it's metal element
Chlorine is in 7A group so it's non-metal element
metal + non metal = ionic
14. The empirical estimation of CAPM suggests that a single market factor is not sufficient to explain the stocks returns. Is this statement true or false
Jawaban:
Estimasi empiris CAPM menunjukkan bahwa faktor pasar tunggal tidak cukup untuk menjelaskan pengembalian saham. Apakah pernyataan ini benar atau salah
Penjelasan:
semoga membantu
15. An unknown monoprotic acid contains only the elements C, H, and O. Combustion analysis indicates that the unknown acid contains 40.0% C and 6.7% H by mass. What is the empirical formula?
Diketahui,
persentase massa
C = 40 %
H = 6,7 %
O = 100 - 40 - 6,7 = 53,3 %
Asumsikan bahwa massa dari asam tersebut adalah 100gr.
Ditanya,
rumus empiris...?
JAWABAN
→ Gunakan persentase massa untuk menghitung massa masing-masing atom.
m(C) = 0,40 x 100 = 40gr
m(H) = 0,067 x 100 = 6,7gr
m(O) = 0,533 x 100 = 53,3gr
→ Hitung jumlah mol masing-masing atom dalam senyawa tersebut (lihat massa atom relatif pada tabel periodik).
n(C) = 40gr : 12,01 gr/mol = 3,330mol
n(H) = 6,7gr : 1,008 gr/mol = 6,64mol
n(O) = 53,3 gr : 16 gr/mol = 3,331mol
→ Karena Karbon(C) memiliki jumlah terkecil, maka atom lain dibagi dengan mol karbon(C).
untuk C;
3,330 mol : 3,330 mol = 1
untuk H;
6,64 mol : 3,330 mol = 1,99(dibulatkan menjadi 2)
untuk O;
3,331 mol : 3,330 mol =
1,003(dibulatkan menjadi 1)
→ Perbandingannya adalah
C:H:O
1:2:1
→ Maka, rumus empirisnya adalah=
CH2O
16. An organic compound contained C 66.7%, H 11.1%, O 22.2% by mass. Its relative formula mass was 72. Find:a the empirical formula of the compoundb the molecular formula of the compound.(A,: H=1, C=12, 0 = 16)mohon dijawab dengan benar dan mohon bantuannya. Terima Kasih
Jawaban:
Ar C = 12
Ar H = 1
Ar O = 16
perbandingan mol
C : H : O
66,7/12 : 11,1/1 : 22,2/16
5,558 : 11,1 : 1,387 (dibagi 1,387)
4 : 8 : 1
the empirical formula => C4H8O
molecular formula => (C4H8O)n = 72
=> (4×12 + 8x1 + 1x16)n = 72
=> (48 + 8 + 16)n = 72
=> 72n = 72
n = 72/72
= 1
if n = 1 the empirical formula = the molecular formula
17. Ditinjau dari fungsinya teori politik memiliki dua nilai yaitu valuational theories dan empirical theories. Namun dalam praktik analisisnya, empirical theories lah yang banyak dibahas. Mengapa?
Jawaban:
Penjelasan:
3. Ditinjau dari fungsinya teori politik memiliki dua nilai yaitu valuational theories dan empirical theories. Namun dalam praktik analisisnya empirical theories lah yang banyak dibahas. Mengapa?
18. Isobutylene is a hydrocarbon used in the manufacture of synthetic rubber. When 0.847 g of isobutylene was subjected to combustion analysis, the gain in mass of the CO2 absorber was 2.657 g and that of the H2O absorber was 1.089 g. What is the empirical formula of isobutylene?
Answer:
CH₂₋
Explanation;
1) Determine the mass of each element in a given mass number of compounds or the mass percent of each element.
Equation of reaction question
subscript C x subscript H subscript y and O 2 produces subscript C O 2 and subscript H 2 O
Mass of space C spaced from space C O subscript 2 is equal to the numerator fraction 1 cross over 12 above the denominator 44 end of the fraction multiplied by cross 2 point 657 equals 0 comma 72 gram space Mass of space H spaced from space H subscript 2 O is equal to the numerator fraction 2 cross times 1 denominator 18 final fraction cross 1 comma 089 equals 0 comma 12 gram spaces
2) Divide the mass of each element by the relative atomic mass, thus obtaining the mole ratio of each atomic ratio. For example, the formula for the compound is: C subscript x H subscript y mole space C colon space mole space H double bond x colon spaced space y mass over Ar C colonic space mass over Ar H double bond x colon spaced space y fraction of numerator 0 comma 72 denominator over 12 end fractions colon space fractional space 0 comma 12 denominator more than 1 ending fraction equal to 0 comma 06 space colon 0 comma 12
3) Convert the obtained comparisons to simple integers.
x space colon space y space equals space 0 comma 06 space colon space 0 comma 12 space equals space 1 space colonize space 2
Therefore, the empirical formula for the compound is the subscript CH2.
19. state the meaning of empirical formula
Jawaban:
rumus empiris
Penjelasan:
menurut saya sih begitu
tolong dimaafkan jika salah
20. 5 .a Calculate the empirical formula of an organic liquid containing 26.67% of carbon and 2.22% of hydrogen, with the rest being oxygen. b The Mr, of the liquid is 90. What is its molecular formula?pls help me
Jawaban:
soalnya5.
5.a Hitung rumus empiris dari cairan organik yang mengandung 26,67% karbon dan 2,22% hidrogen, sisanya adalah oksigen.
5.a Hitung rumus empiris dari cairan organik yang mengandung 26,67% karbon dan 2,22% hidrogen, sisanya adalah oksigen.b Mr, cairan adalah 90. Apakah rumus molekulnya?
jawaban:
a.C : H : O = 26,67/ArC : 2,22/ArH : 71,11/ArO
C : H : O = 26,67/12 : 2,22/1 : 71,1/16
C : H : O = 2,22 : 2,22 : 4,44
C : H : O = 1 : 1 : 2
rumus empirisnya CHO2
sekarang baru kita cari rumus molekulnya
MrCHO2 = (1 . ArC + 1 . ArH + 2 . ArO)n
90 = ( 1(12) + 1(1) + 2(16) ) n
90 = ( 12 + 1 + 32 )n
90 = 45n
n = 2
sehinhga rumus molekulnya
(CHO2)2 => C2H2O4
b.
RM => (HCO2)n=Mr
(Ar H + C + 2O)n = 90
(1+12+32)n=90
(45)n=90
n=2
(HCO2)2
maka RM nya adalah ..
H2C2O4
sorry kalo salah gan
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