(b) The area of triangle ABC is twice the area of triangle DBE.
1. (b) The area of triangle ABC is twice the area of triangle DBE.
Penjelasan dengan langkah-langkah:
[tex]area \: triangle \: abc = \frac{1}{2} \times base \times height \\ = \frac{1}{2} \times 8 \times 14 = 56 \: {cm}^{2} \\ area \: triangle \: abc \: = 2 \times area \: triangle \: dbe \\ 56 = 2 \times area \: triangle \: dbe \\ area \: triangle \: dbe \: = \frac{56}{2} = 28 \: {cm}^{2} [/tex]
2. if one angle of a triangle is equal to the sum of other two angles then the triangle is-:i) an isoscales triangle.ii) an obtuse triangle.iii) an equilateral triangle.iv) a right triangle.
Jawaban:
iii) an equilateral triangle
mungkin
maafkalausalahya.
3. Perimeter of a triangle is 217 cm.the ratio of the triangle sides are 5:9:17 find the length of each side of the triangle
Answer :
Known Values :
Perimeter (P) = 217 cm
Ratio of the sides = 5 : 9 : 17
First, find the value of each "1x" in the ratio ;
=> 217 cm : (5 + 9 + 17)
=> 217 cm : 31
=> 7 cm
Now, we can search each length of each side of the triangle according to the value of each "1x" we searched before.
"A" side :
=> 5 × 7 cm
=> 35 cm
"B" side :
=> 9 × 7 cm
=> 63cm
"C" side :
=> 12 × 7 cm
=> 84cm
So, we found the length for each side in the triangle are 35 cm, 63 cm, and 84 cm.
4. Length of right triangle is (x+2)cm (3x)cm and (4x-6) cm If the circumference is 60 cm. The area of the triangle is ....... cm2
x + 2 + 3x + 4x - 6 = 60
8x - 4 = 60
8x = 64
x = 8
8 + 2 = 10cm
3(8) = 24cm
4(8) - 6 = 26cm
(kali 2 dari segitiga siku-siku 5, 12, 13)
Ini merupakan segitiga siku-siku jadi 10 dan 24 merupakan alas dan tinggi jadi tinggal masukkan ke rumus luas segitiga
10 * 24 * 1/2 = 120 cm^2
ʕっ•ᴥ•ʔっ
[tex] 120 [/tex]
DEFINITION
Circumference is sum of the length of every outer sides.
ANSWER
Let [tex]a[/tex], [tex]b[/tex], and [tex]c[/tex] be the length of right triangle consecutively. Suppose [tex] C [/tex] is the circumference, then by definition
[tex] C = a + b + c \\ \Leftrightarrow C = (x+2)\text{ cm} + 3x \text{ cm} + (4x-6) \text{ cm} \\ \Leftrightarrow C = (8x - 4) \text{ cm} \\ \Leftrightarrow 60 \text{ cm} = (8x - 4) \text{ cm} \\ \Leftrightarrow 60 = 8x - 4 \\ \Leftrightarrow 64 = 8x \\ \therefore \: x = 8 [/tex]
By substituting [tex] x [/tex] with [tex] 8 [/tex], one can obtain
[tex] a = (8+2) \text{ cm} = 10 \text{ cm} \\ b = (3\times 8) \text{ cm} = 24 \text{ cm} \\ c = (4\times 8-6) \text{ cm} = 26 \text{ cm} [/tex]
Since side [tex] c [/tex] is the longest side ([tex] 26 \text{ cm} [/tex]), side [tex] c [/tex] is the hypothenuse.
Then, the area can be calculated as shown below
(Let [tex] A [/tex] be the questioned area)
[tex] A = \frac{1}{2} ab \\ \Leftrightarrow A = \frac{1}{2} \times 10\text{ cm} \times 24\text{ cm} \\ \therefore \: A = 120\text{ cm}^2 [/tex]
CONCLUSION
Therefore, the area of the right triangle is [tex] 120 \text{ cm}^2 [/tex].
5. A piece of wire is bent to form a triangle. The sides of the triangle are in the ratio 3:4:5. The length of the longest side is 35cm. Find the length of the wire used to form the triangle.
[tex] \frac{3 + 4 + 5}{5} \times 35 \: cm \\ \\ \frac{12}{5} \times 35 \: cm = 84 \: cm[/tex]
6. (1)Maing Unknown AnglesIn the following figure, triangle LMO is an equilateral triangle andtriangle MNO is an isosceles triangle. Find ZMNOLM MN12]In the following figure, triangle PQT is an equilateral triangleTriangle PRS is an isosceles triangle. ZQPR = RPS = SPT. Find ZPRSTRS
Jawaban:
120⁰80⁰detail cara dan jawabannya seperti di foto ya.
semangat belajar....
#bintang5dan<3yaaa;))
7. Triangle ABC is similar to triangle XYZ. What is the length of segment BC? * 2 points
Artinya segitiga ABC sebangun dengan segitiga XYZ
Jadi untuk mencari panjang/length of BC
Dengan menggunakan rumus perbandingan
12/x=8/6 (tukar tempat/switch places)
8x = 12 × 6
8x = 72
x = 72/8
x = 9 cm
So the length of segment BC its 9cm
Jadi panjang BC adalah 9cm
8. The lenght of the legs of an isosceles triangle is 4 meters more than its base. If the perimeter of the triangle is 44 meter. Determine the lenghts of the sides of the triangle!bantuin plisss
Jawaban:
4meter x 44meter = 176 meter
Penjelasan dengan langkah-langkah:
Sisi x sisi x sisi
Isosceles triangle = segitiga sama kaki.parimeter = keliling
k= 44m..
kaki nya = 4cm lebih dari sisi bawah.
caranya
K = a + b + c
44 = (4+x) + (4+x) + x
44 = 8 + 3x
44-8 = 3x
36 = 3x
x = 36/3
x = 12
berarti sisi nya =
kaki = 12+ 4 = 16m
sisi bawah = 12m
ini ya kak jawabannya ..
9. What is the sum of all angles of a triangle?
jumlah dari seluruh sisi dari segitiga adalah 3.
semoga membantu ^_^
10. The figure below is made up of Triangle ABC and Triangle ACDABC:36 derajatACD:
Jawaban:
and the question?.....
11. 18. If the size of the angles of triangle are 3x°,4x°and 5x°. The biggest angle of triangle is ...
sudut segitiga = 180°
3x° + 4x° + 5x° = 180°
12x = 180
x = 180/12
x = 15
sudut terbesar = 5x = 5 × 15 = 75°
12. the measures of three sides of a triangle are 9,16,20. determine whether the triangle is a right triangle. explain your answer..
i dont know what you say
13. What is the area of the right triangle shown below
ANSWER:
60.
Penjelasanya :
(theorema phytagoras) a=[tex]\sqrt{b^{2} -c^{2} }[/tex]
a= 17[tex]\sqrt{17^{2}-8^{2} } = \sqrt{289-64}[/tex]
a=[tex]\sqrt{225} =[/tex]15
(the area of the right triangle) :
1/2 x a x h
1/2 x 8 x 15
= 60
ur welcome:)
14. What is the area of the triangle shown below
a = 5
b = 5
c = 8
Keliling
= a + b + c
= 5 + 5 + 8
= 18
s = 1/2 x keliling
s = 1/2 x 18
s = 9
Luas
= √(s(s - a)(s - b)(s - c))
= √(9(9 - 5)(9 - 5)(9 - 8))
= √(9 x 4 x 4 x 1)
= √144
= 12 satuan luas
15. The perimeter of an isosceles triangle is 36 cm. If the base is 10 cm, the area of the triangle is .... cm2. (Pythagorean Theorem)
Penjelasan dengan langkah-langkah:
½ kali 10 kali 36 =
10 kali 36 : 2 =
360 : 2 = 180 cm²
maaf kalo salah ^_^
Pythagorean Theorem"In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides".
Question:
The perimeter of an isosceles triangle is 36 cm. If the base is 10 cm of length, the area of the triangle is ... cm²
Step by step:
Isosceles triangle have 36 cm of its perimeter. The perimeter of triangle is calculated by sum of each side.
Finding length of each leg (x):
36 cm = 10 + x + x
36 = 10 + 2x
26 = 2x
x = 13 cm.
To find the height of triangle, use pythagorean theorem. Let height is written by "y".
[tex]\displaystyle\\y = \sqrt{13^2 - 5^2}\\\\y = \sqrt{169 - 25}\\\\y = \sqrt{144}\\\\y = 12~\text{cm}[/tex]
Calculate the area:
[tex]\text{Area of triangle:}\\\\\boxed{\frac{\text{base}\times\text{height}}{2}}[/tex]
[tex]\displaystyle= \frac{10 \times 12}{2}\\\\= \frac{120}{2}\\\\= 60~\text{cm}^2[/tex]
Conclusion:
The area of an isosceles triangle with 10 cm length of base and 36 cm of its perimeter is 60 cm²
============================
Lesson Category:
(based of the Indonesian Curriculum)
Class: 8th grade of junior high schoolSubject: MathematicsLesson Category: Pythagorean TheoremLesson Code: 8.2.416. Length of right triangle is (x+2)cm (3x)cm and (4x-6) cm If the circumference is 60 cm. The area of the triangle is ....... cm2
[tex](x+2)+(3x)+(4x-6)=(8x-4)=60[/tex]
so, [tex]x=8[/tex]
length of the triangle is 10 cm, 24 cm, and 26, cm
In this triple pytagoras, the area is
[tex]\frac{1}{2} .10.24=120cm^{2}[/tex]
17. A triangle whose base is 6 cm long and height 10 cm. The area of the triangle is… cm2
Answers and explanations:
Base (Alas) = 6 cm
Height (Tinggi) = 10 cm
Area of the Triangle:L = 1/2 x Base x Height
L = 1/2 x 6 x 10 = 30 cm^2
18. If the size of the angles of triangle are 3x°,4x°,5x°.the smallest angle of the triangle is
Jawaban Master Teacher
12x = 180°
x = 15°
smallest angle
3x = 45°19. The base of a triangle is longer than twice its corresponding height by 1 cm. The area of the triangle is 105 cm?. Find the height of the triangle!butuh cepat
Jawaban:
52,5
Penjelasan dengan langkah-langkah:
105:2 sorry if wrong
Jawab:
The height of the triangle is 10 cm.
Penjelasan dengan langkah-langkah:
If the area, base and height of that triangle are notated by A, b and h, then it is known that:
A = (1/2)bh
b = 2h+1
So:
A = (1/2) × (2h+1) × h
A = (1/2) × (2h²+h)
2A = 2h²+h
2×105 = 2h²+h
210 = 2h²+h
2h²+h-210 = 0
(2h+21)(h−10)=0
2h+21=0 or h−10=0
h = -21/2 or h = 10
The positive solution is h = 10, so the height of the triangle is 10 cm.
Proof:
If the height is 10 cm, then the base equals to 21 cm (2×10 + 1 = 21).
The area of the triangle:
A = (1/2)bh = (1/2)(21)(10) = (1/2)(210) = 105 cm². (correct!)
20. The area of a triangle is 528cm2. the length of its base is 33cm. calculate the perpendicular height of the triangle.
Diketahui:
Luas segitiga = 528 cm²
Panjang alas = 33 cm
Tinggi = ?
[tex]luas \: = 528 \\ \frac{1}{2} \times a \times t = 528 \\ \frac{1}{2} \times 33 \times t = 528 \\ t = \frac{528 \times 2}{33} \\ t = 32[/tex]
Jadi, tinggi segitiga adalah 32 cm.
Jawab:
32
Penjelasan dengan langkah-langkah:
L=528
a= 33
L= a*t/2
528= 33*t/2
1056=33t
t= 1056/33
t=32
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