A compound contains 4.04% hydrogen, 24.24% carbon, and 71.72% chlorine. Relative atomic masses: H = 1, C = 12, Cl = 35.5 Relative molecular mass of the compound = 99 Given this information, find the empirical formula and the molecular formula of the compound.
1. A compound contains 4.04% hydrogen, 24.24% carbon, and 71.72% chlorine. Relative atomic masses: H = 1, C = 12, Cl = 35.5 Relative molecular mass of the compound = 99 Given this information, find the empirical formula and the molecular formula of the compound.
Menentukan Rumus Empiris berarti kita menentukan perbandingan paling kecil dari tiap jumlah molekulpertama kita tentukan rumus molekul dengan membagi jumlah kadar atom dengan massa relatifnya
H = 4.04 ÷ 1 = 4,04 dibulatkan ke bawah → 4
C = 24.24 ÷ 12 = 2.02 dibulatkan ke bawah → 2
Cl = 71.72 ÷ 35.5 = 2.02... dibulatkan ke bawah → 2
Didapatkan rumus molekularnya adalah C2H2Cl2Kemudian perkecil perbandingannya maka didapatkan CH2Cl2. An organic compound contained C 66.7%, H 11.1%, O 22.2% by mass. Its relative formula mass was 72. Find:a the empirical formula of the compoundb the molecular formula of the compound.(A,: H=1, C=12, 0 = 16)mohon dijawab dengan benar dan mohon bantuannya. Terima Kasih
Jawaban:
Ar C = 12
Ar H = 1
Ar O = 16
perbandingan mol
C : H : O
66,7/12 : 11,1/1 : 22,2/16
5,558 : 11,1 : 1,387 (dibagi 1,387)
4 : 8 : 1
the empirical formula => C4H8O
molecular formula => (C4H8O)n = 72
=> (4×12 + 8x1 + 1x16)n = 72
=> (48 + 8 + 16)n = 72
=> 72n = 72
n = 72/72
= 1
if n = 1 the empirical formula = the molecular formula
3. Which formula represents the empirical formula of a compound? A.H202 B.C6H12 c. C2H4 D.CH4O
Jawaban:
b.c6h12
Penjelasan:
maaf kalo salah
4. Beryllium forms a compound with chlorine that hasthe empirical formula becl2. how would you determinewhether it is an ionic compound?
Answer :
it's ionic compound
Explain:
because group 1A to 3A is metal element (except hydrogen and boron)
apart from group 1A to 3A, is non-metal element (4A, 5A, 6A, 7A, 8A)
beryllium is in 2A group so it's metal element
Chlorine is in 7A group so it's non-metal element
metal + non metal = ionic
5. isomer dari c7h12 alkuna
ada 13 namanya 1-heptuna 2 heptuna 3 heptuna 3 metil 1 heksuna 4 metil 1 heksuna 5 metil 1 heksuna, 4 metil 2 heksuna, 5 metil 2 heksuna, 2 metil 3 heksuna , 3,3 dimetil 1 pentuna 4,4 dimetil 1 pentuna 3,4 dimetil 1 pentuna 4,4 dimetil 2 pentuna
6. A compound contains one atom of calcium, two atoms of hydrogen and two atoms of oxygen. What is the correct chemical formula of the compound?
Jawaban:
Ca(OH)2
maaf kalau salah
7. Rumus molekul berikut yangtermasuk hidrokarbon tidakjenuh adalah ...,O C4H10 dan C7H12O C5H10 dan C4H10O C6H14 dan C7H12O C5H10 dan C7H12O C4H10 dan C6H14
Jawaban:
C5H10 dan C7H12
Penjelasan:
Hidrokarbon tidak jenuh => hidrokarbon ada ikatan rangkap, dalam hal ini alkena ataupun alkuna. Dalam soal jawaban yg tepat C5H10 dan C7H12
8. isomer posisi dari c7h12
CH3 - CH2 - C_= C - CH2 - CH2 - CH3
9. Compound (Mr = 80) contains 40% mass element X (Ar = 32) and the rest is element Y (Ar = 16). The chemical formula of the compound is
Jawaban:
Massa total = 100%
Ar X = 32
Ar Y = 16
Mr = 80
%Unsur = n x Ar unsur/Mr senyawa x 100%
40% = n x 32/80 x 100%
n = 1
n x Ar X + m x Ar Y = 80
2 x 32 + m x 16 = 80
16m = 16
m = 1
maka senyawa = XY
10. A possible molecular formula for a gas with density 1.43g/L at STP is
Mass: 1.43 g/L × 22.4 L/mol = 32 g/mol
Possible formula is O2
#ChemistryIsFun
11. apakah C7H12 senyawa alkena
Jawaban:
bukan C7H12 merupakan senyawa alkuna
Penjelasan:
alkena rumus senyawanya CnH2n, kalau alkana CnH2n+2, alkuna Cn H2n-2
12. isomer dari alkena c7h12
Cn H2 n semoga membantu
13. isomer kerangka C7H12
ada 6 Isomer pd rumus molekul C7H12
14. isomer alkuna dari c7h12
1 heptuna CH≡C-CH2-CH2-CH2-CH2-CH3
2 heptuna CH3-C≡C-CH2-CH2-CH2-CH3
3 heptuna CH3-CH2-C≡C-CH2-CH2-CH3
3 metil 1 heksuna CH≡C-CH(CH3)-CH2-CH2-CH3
4 metil 1 heksuna CH≡C-CH2-CH(CH3)-CH2-CH3
5 metil 1 heksuna CH≡C-CH2-CH2-CH(CH3)-CH3
4 metil 2 heksuna
5 metil 2 heksuna
2 metil 3 heksuna
15. rumus keisomeran C7H12
CnHn+5 .......................
16. Rumah struktur C7H12
C7H12 merupakan senyawa hidrokarbon tak jenuh dengan rangkap tiga.
namanya yaitu : 1 heptuna, 2 heptuna, 3 heptuna, 3 metil 1 heksuna, 4 metil 1 heksuna, 5 metil 1 heksuna, 4 metil 2 heksuna, 5 metil 2 heksuna, 2 dimetil 3 heksuna, 3,3 dimetil 1 pentuna, 4,4 dimetil 1 pentuna, 3,4 dimetil 1 pentuna, 4,4 dimetil 2 pentun.jawaban terlampir.
Semoga bermanfaat
17. banyak isomer dari c7h12
perhatikan gambar pada foto ya, itu yang sudah saya susun..mungkin ada yang mau menambahkan
18. A Coumpound of nitrogen and oxygen has the formula NO. in this compound there are 1.143 b of oxygen for each 1.00g of nitrogen.A difreng compound of nitrogen and oxygen has the formula NO2. How many grams of oxygen would be combined with each 1.00g of nitrogen in NO2? a. 2.286g O b. 1.000g O c. 0.5715g O d. 4.572g O e. 2.000g O Mohon bantu dengan Caranya ;)
N2+2O2→2NO2
perbandingan mol N2 dan O2 adalah 1:2
1gram N2= 1:28 mol= 0.0357142857 mol,,,
jadi mol O2 = 0.0714285714 mol
jadi massa O2= 0.0714285714 x 32 = 2.2857142848gram
A
19. A compound of nitrogen and oxygen has the formula NO. In this compund there are 8/7 g of oxygen for each 1 g of nitrogen. A different compound has the formula N2O. How many grams of oxygen would combined with each 1 g of nitrogen in N20? a. 4/7 g b. 1 g c. 8/7 g d. 2/7 g e. 16/7 g
Matter : Stoichiometry
Sub matter : Dalton's Law
Weigh of O = 8/7 gram of N
Ratio mass of NO:
N ÷ O = 7 ÷ 8
Compound N2O:
2×N ÷ O = 7 ÷ 8
2 ÷ O = 7 ÷ 8
O = 16/7
Answer is E.
#ChemistryIsFun
20. The compound microscope has not one ______ two lenses
Jawaban:
the compound microscope has not one "but" two lenses
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